Splitting of articles by article ids
Jump to navigation
Jump to search
Case1: Articles Numbered IDs[edit]
If the article number is a digit, split the article into two parts based on a remainder of 0 or 1, resulting in two nearly equal halves.
(1) Part1
SELECT * FROM articles WHERE MOD(article_id, 2) = 0;
(2) Part2
SELECT * FROM articles WHERE MOD(article_id, 2) = 1;
Case2: Articles IDs which mix of string and number[edit]
If the article ID consists of numbers or text e.g. Amazon Standard Identification Number, it is divided into two parts after a formula calculation with the remainder equal to 0 or 1, resulting in two parts of different quantities.
CONV(HEX(article_id), 16, 10) converts HEX(article_id) from hexadecimal (base 16) to decimal (base 10). Then, MOD(CONV(HEX(article_id), 16, 10), 2) computes the remainder when the converted decimal number is divided by 2.
(1) Create test data
SET NAMES utf8mb4;
DROP TABLE IF EXISTS `strnum_article_ids`;
CREATE TABLE `strnum_article_ids` (
`article_id` char(50) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL,
`content` text CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_vietnamese_ci;
INSERT INTO `strnum_article_ids` (`article_id`, `content`) VALUES
('ap1p3le3', 'apple'),
('or2an3ge4', 'orange'),
('ba34na5na', 'banana'),
('wate4rle56mon', 'waterlemon'),
('ki78wi', 'kiwi');
(2) Part 1
SELECT * FROM `strnum_article_ids` WHERE MOD(CONV(HEX(article_id), 16, 10), 2) = 0;
(3) Part 2
SELECT * FROM `strnum_article_ids` WHERE MOD(CONV(HEX(article_id), 16, 10), 2) = 1;