Sleep
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Sleep random seconds in programming
MS-DOS
Approach 1: %RANDOM% + ping local
batch file - .bat random timeout - Stack Overflow
- %RANDOM% returns an integer between 0 and 32767.
- 60 is the range of values you want: 0 to 60.
- 32768 is the range of values returned by %RANDOM% (0 to 32767).
- 5 is the minimum value you want. The original range of values you want '0 to 60' became '5 ~ 65'.
- ping local address[1]
BAT file:
REM print current date & time ECHO %date% %time% REM sleep 5 ~ 65 seconds SET /a timeout=%RANDOM% * 60 / 32768 + 5 ping 127.0.0.1 -n %timeout% > nul REM print current date & time ECHO %date% %time%
Approach 2: sleep package of CygWin
Requirement: Install Cygwin on Win 
& install sleep package
Verify the installation of sleep package[2][3]
- Key-in cmd to open command prompt (How to Open Command Prompt (Windows 10, 8, 7, Vista, XP))
- Key-in where sleep or dir C:\cygwin64\bin\sleep.exe if the installation path of CygWin is C:\cygwin64\.
# successful condition C:\Users\user>dir C:\cygwin64\bin\sleep.exe C:\cygwin64\bin\sleep.exe # failed condition File Not Found
BAT file:
REM print current date & time ECHO %date% %time% REM sleep 5 ~ 65 seconds SET /a timeout=%RANDOM% * 60 / 32768 + 5 C:\cygwin64\bin\sleep.exe %timeout% REM print current date & time ECHO %date% %time%
Approach 3: TIMEOUT
Alternative command: 
The following command ECHO %date% %time% will not be executed after TIMEOUT %timeout% was executed.
BAT file:
SET /a timeout=%RANDOM% * 60 / 32768 + 5 TIMEOUT %timeout% ECHO %date% %time%